Searched refs:num_subfr (Results 1 – 1 of 1) sorted by relevance
217 int num_subfr) in sipr_decode_lp() argument221 float t, t0 = 1.0 / num_subfr; in sipr_decode_lp()224 for (i = 0; i < num_subfr; i++) { in sipr_decode_lp()