Searched refs:aOrderBy (Results 1 – 4 of 4) sorted by relevance
7130 } *aOrderBy; /* The ORDER BY clause */ member
5892 if( pIdxInfo->aOrderBy[0].desc ){ in seriesBestIndex()9746 int iCol = pIdxInfo->aOrderBy[i].iColumn; in expertBestIndex()9751 pNew->bDesc = pIdxInfo->aOrderBy[i].desc; in expertBestIndex()11508 if( pTab->bPtr==0 && pIdx->nOrderBy && pIdx->aOrderBy[0].desc==0 ){ in dbdataBestIndex()11509 int iCol = pIdx->aOrderBy[0].iColumn; in dbdataBestIndex()11512 }else if( pIdx->nOrderBy==2 && pIdx->aOrderBy[1].desc==0 && iCol==0 ){ in dbdataBestIndex()11513 pIdx->orderByConsumed = (pIdx->aOrderBy[1].iColumn==1); in dbdataBestIndex()
7443 } *aOrderBy; /* The ORDER BY clause */ member151935 p->aOrderBy[i].iColumn,151936 p->aOrderBy[i].desc);152280 pIdxInfo->aOrderBy = pIdxOrderBy;175031 struct sqlite3_index_orderby *pOrder = &pInfo->aOrderBy[0];179583 && pInfo->aOrderBy[0].iColumn==0179584 && pInfo->aOrderBy[0].desc==0208073 && pIdxInfo->aOrderBy[0].iColumn==0208074 && pIdxInfo->aOrderBy[0].desc==0208077 && pIdxInfo->aOrderBy[0].iColumn==0[all …]
82771 + if( pIdxInfo->nOrderBy>=1 && pIdxInfo->aOrderBy[0].iColumn==0 ){82772 + if( pIdxInfo->aOrderBy[0].desc ){86595 - if( pIdxInfo->aOrderBy[0].desc ){91392 +** sort order defined by the "nOrderBy" and "aOrderBy" fields of the91401 +** "aOrderBy" field are adjacent.)^ This mode is used when the query planner91406 +** order, as long as rows with the same values in all "aOrderBy" columns91408 +** combination of values in the columns identified by the "aOrderBy" field91410 +** values in all "aOrderBy" columns to be returned, as long as all such rows91412 +** that have the same value for all columns identified by "aOrderBy".91419 +** rows that are identical in all aOrderBy columns, if it wants to, but[all …]