Searched refs:cbrt_2deriv (Results 1 – 5 of 5) sorted by relevance
| /third_party/boost/libs/math/example/ |
| D | root_finding_multiprecision_example.cpp | 45 T cbrt_2deriv(T x) in cbrt_2deriv() function
153 T r = cbrt_2deriv(value); in show_cube_root()
182 cpp_dec_float_50 r = cbrt_2deriv(two); in main()
185 r = cbrt_2deriv(2.); // Passing a double, so ADL will compute a double precision result. in main()
188 r = cbrt_2deriv(static_cast<cpp_dec_float_50>(2.)); // Passing a cpp_dec_float_50, in main()
191 …r = cbrt_2deriv<cpp_dec_float_50>(2.); // Explicitly a cpp_dec_float_50, so will compute a cpp_dec… in main()
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| D | root_finding_start_locations.cpp | 114 boost::uintmax_t cbrt_2deriv(T x, T guess) in cbrt_2deriv() function
348 << cbrt_2deriv(to_root, answer / 6) in main()
349 << "][" << cbrt_2deriv(to_root, answer / 2) in main()
350 << "][" << cbrt_2deriv(to_root, answer - answer * 0.5) in main()
351 << "][" << cbrt_2deriv(to_root, answer - answer * 0.2) in main()
352 << "][" << cbrt_2deriv(to_root, answer - answer * 0.1) in main()
353 << "][" << cbrt_2deriv(to_root, answer - answer * 0.05) in main()
354 << "][" << cbrt_2deriv(to_root, answer + answer * 0.05) in main()
355 << "][" << cbrt_2deriv(to_root, answer + answer * 0.1) in main()
356 << "][" << cbrt_2deriv(to_root, answer + answer * 0.2) in main()
[all …]
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| D | root_finding_example.cpp | 283 T cbrt_2deriv(T x) in cbrt_2deriv() function
466 r = cbrt_2deriv(threecubed); in main()
468 r = cbrt_2deriv(threecubedp1); in main()
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| D | root_finding_algorithms.cpp | 298 T cbrt_2deriv(T x) in cbrt_2deriv() function
514 result = cbrt_2deriv(to_root); // in test_root()
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| /third_party/boost/libs/math/doc/roots/ |
| D | root_finding_examples.qbk | 172 cbrt_2deriv(28) = 3.0365889718756627
367 `cpp_dec_float_50 r = cbrt_2deriv(2);` or `show_cube_root(2);`
373 Even more treacherous is passing a `double` as in `cpp_dec_float_50 r = cbrt_2deriv(2.);`
376 Making the `cbrt` type explicit with `cbrt_2deriv<cpp_dec_float_50>(2.);` will give you the desired…
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