Searched refs:dq3 (Results 1 – 2 of 2) sorted by relevance
316 ABS1 m11, m13 ; 0dq0, 0dq3 , 1dq0, 1dq3
1532 const int dq3 = abs(TQ2 - 2 * TQ1 + TQ0); in FUNC() local1534 const int d3 = dp3 + dq3; in FUNC()1579 if (dq0 + dq3 < ((beta + (beta >> 1)) >> 3)) in FUNC()