Searched refs:BI_CLAUSE_SUBWORD_TUPLE_0 (Results 1 – 3 of 3) sorted by relevance
30 #define T(x) ((enum bi_clause_subword)(BI_CLAUSE_SUBWORD_TUPLE_0 + x))
254 BI_CLAUSE_SUBWORD_TUPLE_0 = 8, enumerator285 #define T(x) ((enum bi_clause_subword)(BI_CLAUSE_SUBWORD_TUPLE_0 + x))
484 assert(idx >= BI_CLAUSE_SUBWORD_TUPLE_0); in bi_pack_tuple_bits()487 unsigned val = (idx - BI_CLAUSE_SUBWORD_TUPLE_0); in bi_pack_tuple_bits()