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1/*
2 * Copyright (c) 2023 Huawei Device Co., Ltd.
3 * Licensed under the Apache License, Version 2.0 (the "License");
4 * you may not use this file except in compliance with the License.
5 * You may obtain a copy of the License at
6 *
7 *     http://www.apache.org/licenses/LICENSE-2.0
8 *
9 * Unless required by applicable law or agreed to in writing, software
10 * distributed under the License is distributed on an "AS IS" BASIS,
11 * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
12 * See the License for the specific language governing permissions and
13 * limitations under the License.
14 */
15
16import * as crypto from 'crypto';
17
18export class ListUtil {
19  public static readonly MAX_INIT_LEN: number = 0xFFFF;
20
21  /**
22   * get a list with element number filled for each element
23   * @param length: list length you want init.
24   */
25  public static getInitList(length: number): number[] {
26    if (isNaN(length) || length < 0 || length > this.MAX_INIT_LEN) {
27      console.error(`array init length is invalid, should in range: [0, ${this.MAX_INIT_LEN}]`);
28      return [];
29    }
30
31    return Array(length).fill(null).map((_, h) => h);
32  }
33
34  /**
35   * shuffle list
36   * @param originList: list to be shuffled
37   */
38  public static shuffle(originList: number[]): void {
39    if (!originList) {
40      return;
41    }
42
43    for (let i = originList.length; i > 0; i--) {
44      let j = crypto.randomInt(originList.length);
45      [originList[i - 1], originList[j]] = [originList[j], originList[i - 1]];
46    }
47  }
48
49  /**
50   * merge two list to one list of unique element
51   * @param listA
52   * @param listB
53   * @param listC
54   */
55  public static uniqueMergeList(listA: string[], listB: string[], listC?: string[]): string[] {
56    const firstList: string[] = listA ? listA : [];
57    const secondList: string[] = listB ? listB : [];
58    const thirdList: string[] = listC ? listC : [];
59
60    const tmpList: string[] = thirdList ? [...firstList, ...secondList, ...thirdList] : [...firstList, ...secondList];
61    const elementSet: Set<string> = new Set<string>(tmpList);
62    return Array.from(elementSet);
63  }
64}
65