Searched refs:BI_CLAUSE_SUBWORD_LITERAL_0 (Results 1 – 3 of 3) sorted by relevance
249 BI_CLAUSE_SUBWORD_LITERAL_0 = 0, enumerator283 #define L(x) ((enum bi_clause_subword)(BI_CLAUSE_SUBWORD_LITERAL_0 + x))
448 assert(literal >= BI_CLAUSE_SUBWORD_LITERAL_0); in bi_pack_literal()451 return (literal - BI_CLAUSE_SUBWORD_LITERAL_0); in bi_pack_literal()
28 #define L(x) ((enum bi_clause_subword)(BI_CLAUSE_SUBWORD_LITERAL_0 + x))