Lines Matching full:ld8
243 EX(3f,(p16) ld8 val1[1]=[src1],8); \
352 // Stop bit not required after ld8 because if we fail on ld8
355 EX(.failure_in1,(p9) ld8 val2[1]=[src1],8) // 8-byte aligned
377 EX(.failure_in3,(p16) ld8 val1[0]=[src1],16)
378 (p16) ld8 val2[0]=[src2],16
391 EX(.failure_in1,(p6) ld8 val1[0]=[src1],8) // at least 8 bytes
505 // ld8(). Given the way the code is written today, this means only
510 // - if you fail on the ld8 in the head, it means you went straight
512 // Again this comes from the fact that if you crossed just for the ld8 then
514 // either go for the 16byte copy loop OR the ld8 in the tail part.
515 // The combination ld1, ld2, ld4, ld8 where you fail on ld8 is impossible
534 // 2 or 3 bytes left to copy and we did not execute the ld8 nor ld4.