Searched refs:ulp (Results 1 – 16 of 16) sorted by relevance
690 dval(rv) += adj*ulp(dval(rv)); in strtod()696 dval(rv) += adj*ulp(dval(rv)); in strtod()719 adj *= ulp(dval(rv)); in strtod()729 adj *= ulp(dval(rv)); in strtod()838 dval(rv) += ulp(dval(rv)); in strtod()841 dval(rv) -= ulp(dval(rv)); in strtod()899 adj = aadj1 * ulp(dval(rv)); in strtod()923 adj = aadj1 * ulp(dval(rv)); in strtod()930 adj = aadj1 * ulp(dval(rv)); in strtod()949 adj = aadj1 * ulp(dval(rv)); in strtod()[all …]
38 ulp in ulp() function
541 #define ulp __ulp_D2A macro589 extern double ulp (double);
71 ulp.c
17 the last place (1 ulp) from what it should be. (Bug discovered by Paul
986 ulp(U *x) in ulp() function1329 return ulp(x); in sulp()2134 adj.d = aadj1 * ulp(&rv); in _Py_dg_strtod()2165 adj.d = aadj1 * ulp(&rv); in _Py_dg_strtod()
1003 ulp(U *x) in ulp() function1346 return ulp(x); in sulp()2165 adj.d = aadj1 * ulp(&rv); in _Py_dg_strtod()2196 adj.d = aadj1 * ulp(&rv); in _Py_dg_strtod()
479 -- next may be a > 0.5ulp case; a more precise answer is:549 -- next may be a > 0.5ulp case; a more precise answer is:
23 -- show results which are correctly rounded (within <= 0.5 ulp).
376 -- ulp replacement tests
385 -- ulp replacement tests
419 -- ulp replacement tests1938 -- ulp replacement tests
1558 -- these are likely to show > 0.5 ulp error for very small powers
1177 -- ulp replacement tests2649 -- ulp replacement tests
921 -- ulp replacement tests
944 -- ulp replacement tests