Searched refs:TreeNodePtr (Results 1 – 1 of 1) sorted by relevance
54 using TreeNodePtr = DomTreeNodeBase<NodeT> *; member173 TreeNodePtr getNodeForBlock(NodePtr BB, DomTreeT &DT) { in getNodeForBlock()174 if (TreeNodePtr Node = DT.getNode(BB)) return Node; in getNodeForBlock()181 TreeNodePtr IDomNode = getNodeForBlock(IDom, DT); in getNodeForBlock()196 BlockNamePrinter(TreeNodePtr TN) : N(TN ? TN->getBlock() : nullptr) {} in BlockNamePrinter()316 const TreeNodePtr TN = DT.getNode(N);585 void attachNewSubtree(DomTreeT& DT, const TreeNodePtr AttachTo) { in attachNewSubtree()600 TreeNodePtr IDomNode = getNodeForBlock(ImmDom, DT); in attachNewSubtree()609 void reattachExistingSubtree(DomTreeT &DT, const TreeNodePtr AttachTo) { in reattachExistingSubtree()613 const TreeNodePtr TN = DT.getNode(N); in reattachExistingSubtree()[all …]