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Searched refs:hourDigit2 (Results 1 – 1 of 1) sorted by relevance

/external/icu/icu4c/source/i18n/
Ddayperiodrules.cpp266 int32_t hourDigit2 = time[1] - 0x30; in parseHour() local
267 if (hourDigit2 < 0 || 9 < hourDigit2) { in parseHour()
271 hour = hour * 10 + hourDigit2; in parseHour()