Searched refs:kFullFontName (Results 1 – 2 of 2) sorted by relevance
60 case NameId::kFullFontName: in ConstructName()118 if (name_id == NameId::kFullFontName) { in HashCode()149 case NameId::kFullFontName: in HasName()
45 kFullFontName = 4, enumerator