Searched refs:memAllocL0Size (Results 1 – 1 of 1) sorted by relevance
19 mem [memAllocL1Size]*[memAllocL0Size]uint6420 buf [memAllocL0Size]uint6426 memAllocL0Size = 64 const28 memAllocL0Mem = memAllocL0Size * memAllocGranule * bitsPerUint6479 for i1 := uint64(0); i1 < ma.size/(memAllocL0Size*bitsPerUint64); i1++ {90 i1 = idx / (memAllocL0Size * bitsPerUint64)91 r1 := idx % (memAllocL0Size * bitsPerUint64)100 ma.mem[i1] = new([memAllocL0Size]uint64)