Searched refs:n0 (Results 1 – 12 of 12) sorted by relevance
125 double n0 = 2 * (x[0] * (v0 * x[0] - (x[2] * v2 - x[3] * v1)) + s * x[1]) - v0; in rotateVec() local129 return new double[]{n0, n1, n2}; in rotateVec()
13 set APP_BASE_NAME=%~n0
16 set APP_BASE_NAME=%~n0
856 for (Node n0 : mNodes) { in calcOrder()857 if (n0.mInputs.size() == 0) { in calcOrder()861 ret &= calcOrderRecurse(n0, 1); in calcOrder()
756 bool operator()(const Key* n0, const Key* n1) const { return *n0 < *n1; } in operator()