Searched refs:TimeFromYear (Results 1 – 1 of 1) sorted by relevance
65 double TimeFromYear(int y) { in TimeFromYear() function76 return TimeFromYear(y) + ((double)pMonth[m]) * 86400000; in TimeFromYearMonth()86 if (TimeFromYear(y) <= t) { in YearFromTime()87 while (TimeFromYear(y + 1) <= t) in YearFromTime()90 while (TimeFromYear(y) > t) in YearFromTime()177 double t1 = TimeFromYear(year); in JS_GetDateTime()