Searched refs:subfr_nr (Results 1 – 1 of 1) sorted by relevance
536 int subfr_nr, int nb_subfr, in int_lpc_acelp() argument546 fac_old = lsp_interpol_factor[nb_subfr & 0x1][(nb_subfr - 1) - subfr_nr]; in int_lpc_acelp()547 fac_new = lsp_interpol_factor[nb_subfr & 0x1][subfr_nr]; in int_lpc_acelp()738 int i_subfr, subfr_nr, l_div, T; in CLpd_AcelpDecode() local788 for (i_subfr = 0, subfr_nr = 0; i_subfr < l_div; in CLpd_AcelpDecode()789 i_subfr += L_SUBFR, subfr_nr++) { in CLpd_AcelpDecode()796 T0 = (int)pAcelpData->T0[subfr_nr]; in CLpd_AcelpDecode()797 T0_frac = (int)pAcelpData->T0_frac[subfr_nr]; in CLpd_AcelpDecode()806 if ((!bfi && pAcelpData->ltp_filtering_flag[subfr_nr] == 0) || in CLpd_AcelpDecode()823 D_ACELP_decode_4t64(pAcelpData->icb_index[subfr_nr], nbits, &code[0]); in CLpd_AcelpDecode()[all …]