Searched defs:splitPerm (Results 1 – 3 of 3) sorted by relevance
148 val splitPerm = spi.splitPermission in <lambda>() constant
422 SplitPermissionInfo splitPerm = splitPerms.get(i); in parseFromXml() local
153 PermissionManager.SplitPermissionInfo splitPerm = splitPerms.get(splitPermNum); in addSplitPermissions() local