Searched refs:filename_in_mount (Results 1 – 3 of 3) sorted by relevance
24 filename_in_mount = args[0]25 logging.debug('Parse %s...', filename_in_mount)26 with file_accessor.prepare_file(filename_in_mount) as filename:
110 def prepare_file(self, filename_in_mount): argument128 filename_in_storage = self._get_pathfile_to_access(filename_in_mount)