Searched refs:allFilesByName (Results 1 – 1 of 1) sorted by relevance
417 allFilesByName map[string]*FileDescriptor // All files by filename. member725 g.allFilesByName = make(map[string]*FileDescriptor, len(g.allFiles))767 g.allFilesByName[f.GetName()] = fd775 fd := g.allFilesByName[fileName]1272 return g.allFilesByName[filename]