Searched refs:inbits (Results 1 – 1 of 1) sorted by relevance
2280 long inbits = Double.doubleToLongBits(x); in reducePayneHanek() local2281 int exponent = (int) ((inbits >> 52) & 0x7ff) - 1023; in reducePayneHanek()2284 inbits &= 0x000fffffffffffffL; in reducePayneHanek()2285 inbits |= 0x0010000000000000L; in reducePayneHanek()2289 inbits <<= 11; in reducePayneHanek()2310 long a = inbits >>> 32; in reducePayneHanek()2311 long b = inbits & 0xffffffffL; in reducePayneHanek()3223 long inbits = Double.doubleToLongBits(x); in cbrt() local3224 int exponent = (int) ((inbits >> 52) & 0x7ff) - 1023; in cbrt()3235 inbits = Double.doubleToLongBits(x); in cbrt()[all …]