Searched refs:kNumberOfAllocations (Results 1 – 1 of 1) sorted by relevance
65 const int kNumberOfAllocations = 10000; variable86 for (int i = 0; i < kNumberOfAllocations; ++i) in Run()95 for (int i = 0; i < kNumberOfAllocations; ++i) in Run()131 intptr_t expected = sum.first * kNumberOfAllocations; in CheckAllocationPattern()147 for (int i = 0; i < kNumberOfAllocations; ++i) in TEST_F()156 for (int i = 0; i < kNumberOfAllocations; ++i) { in TEST_F()