Searched refs:squareRoot (Results 1 – 2 of 2) sorted by relevance
195 BigInteger squareRoot = null; in modSqrt() local205 squareRoot = x.modPow(q, p); in modSqrt()245 squareRoot = u; in modSqrt()250 if (squareRoot != null && squareRoot.multiply(squareRoot).mod(p).compareTo(x) != 0) { in modSqrt()253 return squareRoot; in modSqrt()
3803 void __attribute__((__swift_name__("squareRoot()"))) sqrt(double v) {