Searched refs:bitsPerDigit (Results 1 – 1 of 1) sorted by relevance
462 long numBits = ((numDigits * bitsPerDigit[radix]) >>> 10) + 1; in BigInteger()519 long numBits = ((numDigits * bitsPerDigit[10]) >>> 10) + 1; in BigInteger()564 private static long bitsPerDigit[] = { 0, 0, field in BigInteger