Searched refs:digit_i (Results 1 – 1 of 1) sorted by relevance
216 uint8_t digit_i = ueid_vec[i + 1]; in ueid_to_imei_blob() local218 imei_string[i] = '0' + digit_i; in ueid_to_imei_blob()219 luhn_digit_sum += i % 2 == 0 ? digit_i : digit_i * 2 / 10 + (digit_i * 2) % 10; in ueid_to_imei_blob()