Searched refs:MAX_PKT_NUM_LEN (Results 1 – 2 of 2) sorted by relevance
49 pub const MAX_PKT_NUM_LEN: usize = 4; constant431 let mut pn_and_sample = b.peek_bytes_mut(MAX_PKT_NUM_LEN + SAMPLE_LEN)?; in decrypt_hdr()433 let (mut ciphertext, sample) = pn_and_sample.split_at(MAX_PKT_NUM_LEN)?; in decrypt_hdr()
3213 max_len = max_len.saturating_sub(packet::MAX_PKT_NUM_LEN); in dgram_max_writable_len()