Searched refs:_DI400Y (Results 1 – 2 of 2) sorted by relevance
85 _DI400Y = _days_before_year(400) # number of days in 400 years variable95 n400 = (n-1)//_DI400Y # # of 400-year blocks preceding96 year, n = 400 * n400, n - _DI400Y * n400
71 _DI400Y = _days_before_year(401) # number of days in 400 years variable81 assert _DI400Y == 4 * _DI100Y + 1111 n400, n = divmod(n, _DI400Y)2542 del (_DAYNAMES, _DAYS_BEFORE_MONTH, _DAYS_IN_MONTH, _DI100Y, _DI400Y,