Searched refs:kDx (Results 1 – 2 of 2) sorted by relevance
47 kDx = 2, enumerator59 || this->has(kDx) in hasAny()
164 attrs[PosAttrs::kDx] = fDx[localCharIndex]; in resolve()337 pos.has(PosAttrs::kDx) ? pos[PosAttrs::kDx] : 0, in shapeFragment()