Searched refs:numZeroes (Results 1 – 2 of 2) sorted by relevance
35 uint32_t numZeroes = 0; in parseUE() local37 ++numZeroes; in parseUE()39 uint32_t val = br->getBits(numZeroes); in parseUE()40 return val + (1u << numZeroes) - 1; in parseUE()
371 int numZeroes = decimalFormatPatternType.length() - 1; in addPaths() local372 int baseZeroes = (numZeroes / 3) * 3; in addPaths()