Searched refs:FAT12 (Results 1 – 8 of 8) sorted by relevance
| /external/mtools/ |
| D | msdos.h | 214 #define FAT12 0x0ff5 /* max. number + 1 of clusters described by a 12 bit FAT */ macro
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| D | fat_size_calculation.tex | 41 Number of nubbles (4 bit unit per FAT). This is 3 for FAT12, 4 for
172 number of clusters allowable for FAT12 or FAT16), we need to shrink
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| D | fat.c | 606 if(This->num_clus < FAT12) in set_fat()
749 if(This->num_clus >= FAT12) in old_fat_read()
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| D | mformat.c | 289 if(rem_sect > 256 * FAT12) in calc_fat_len()
428 maxClus = FAT12; in try_cluster_size()
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| D | mtools.info | 1745 For FAT12 and FAT16, mformat uses an iterative approach, where it
2018 65536 sectors of the disk, assign 0x01 ("'DOS FAT12, CHS'") for
2019 FAT12 partition and 0x04 ("'DOS FAT16, CHS'") for FAT16 partitions
2027 definition), then FAT12 is assumed for all drives with less than 4096
2036 with less than 32680 sectors to be FAT12. Mtools uses 4096 sectors
2037 as the cutoff point, as older versions of DOS only support FAT12 on
2039 ones which would be most likely to use FAT12 in the first place).
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| D | mtools.texi | 1949 For FAT12 and FAT16, mformat uses an iterative approach, where it
2266 sectors of the disk, assign 0x01 (``@code{DOS FAT12, CHS}'') for FAT12
2278 definition), then FAT12 is assumed for all drives with less than 4096
2289 less than 32680 sectors to be FAT12. Mtools uses 4096 sectors as the
2290 cutoff point, as older versions of DOS only support FAT12 on disks
2292 which would be most likely to use FAT12 in the first place).
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| D | NEWS | 172 Fix mformat'ing of FAT12 filesystems with huge cluster sizes
356 Fixed max numbers of sectors for FAT12 and FAT16 (was off by one...)
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| /external/mtools/debian/ |
| D | changelog | 201 * Fix mformat'ing of FAT12 filesystems with huge cluster sizes
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