Searched refs:kFullFontName (Results 1 – 2 of 2) sorted by relevance
62 case NameId::kFullFontName: in ConstructName()120 if (name_id == NameId::kFullFontName) { in HashCode()151 case NameId::kFullFontName: in HasName()
45 kFullFontName = 4, enumerator