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1 /* ELF string table handling.
2    Copyright (C) 2000, 2001, 2002 Red Hat, Inc.
3    Written by Ulrich Drepper <drepper@redhat.com>, 2000.
4 
5    This program is Open Source software; you can redistribute it and/or
6    modify it under the terms of the Open Software License version 1.0 as
7    published by the Open Source Initiative.
8 
9    You should have received a copy of the Open Software License along
10    with this program; if not, you may obtain a copy of the Open Software
11    License version 1.0 from http://www.opensource.org/licenses/osl.php or
12    by writing the Open Source Initiative c/o Lawrence Rosen, Esq.,
13    3001 King Ranch Road, Ukiah, CA 95482.   */
14 
15 #ifdef HAVE_CONFIG_H
16 # include <config.h>
17 #endif
18 
19 #include <assert.h>
20 #include <inttypes.h>
21 #include <libelf.h>
22 #include <stddef.h>
23 #include <stdlib.h>
24 #include <string.h>
25 #include <unistd.h>
26 #include <sys/param.h>
27 
28 #include "libebl.h"
29 #include <system.h>
30 
31 #ifndef MIN
32 # define MIN(a, b) ((a) < (b) ? (a) : (b))
33 #endif
34 
35 
36 struct Ebl_Strent
37 {
38   const char *string;
39   size_t len;
40   struct Ebl_Strent *next;
41   struct Ebl_Strent *left;
42   struct Ebl_Strent *right;
43   size_t offset;
44   char reverse[0];
45 };
46 
47 
48 struct memoryblock
49 {
50   struct memoryblock *next;
51   char memory[0];
52 };
53 
54 
55 struct Ebl_Strtab
56 {
57   struct Ebl_Strent *root;
58   struct memoryblock *memory;
59   char *backp;
60   size_t left;
61   size_t total;
62   bool nullstr;
63 
64   struct Ebl_Strent null;
65 };
66 
67 
68 /* Cache for the pagesize.  We correct this value a bit so that `malloc'
69    is not allocating more than a page.  */
70 static size_t ps;
71 
72 
73 struct Ebl_Strtab *
ebl_strtabinit(bool nullstr)74 ebl_strtabinit (bool nullstr)
75 {
76   struct Ebl_Strtab *ret;
77 
78   if (ps == 0)
79     {
80       ps = sysconf (_SC_PAGESIZE) - 2 * sizeof (void *);
81       assert (sizeof (struct memoryblock) < ps);
82     }
83 
84   ret = (struct Ebl_Strtab *) calloc (1, sizeof (struct Ebl_Strtab));
85   if (ret != NULL)
86     {
87       ret->nullstr = nullstr;
88 
89       if (nullstr)
90 	{
91 	  ret->null.len = 1;
92 	  ret->null.string = "";
93 	}
94     }
95 
96   return ret;
97 }
98 
99 
100 static int
morememory(struct Ebl_Strtab * st,size_t len)101 morememory (struct Ebl_Strtab *st, size_t len)
102 {
103   struct memoryblock *newmem;
104 
105   if (len < ps)
106     len = ps;
107   newmem = (struct memoryblock *) malloc (len);
108   if (newmem == NULL)
109     return 1;
110 
111   newmem->next = st->memory;
112   st->memory = newmem;
113   st->backp = newmem->memory;
114   st->left = len - offsetof (struct memoryblock, memory);
115 
116   return 0;
117 }
118 
119 
120 void
ebl_strtabfree(struct Ebl_Strtab * st)121 ebl_strtabfree (struct Ebl_Strtab *st)
122 {
123   struct memoryblock *mb = st->memory;
124 
125   while (mb != NULL)
126     {
127       void *old = mb;
128       mb = mb->next;
129       free (old);
130     }
131 
132   free (st);
133 }
134 
135 
136 static struct Ebl_Strent *
newstring(struct Ebl_Strtab * st,const char * str,size_t len)137 newstring (struct Ebl_Strtab *st, const char *str, size_t len)
138 {
139   struct Ebl_Strent *newstr;
140   size_t align;
141   int i;
142 
143   /* Compute the amount of padding needed to make the structure aligned.  */
144   align = ((__alignof__ (struct Ebl_Strent)
145 	    - (((uintptr_t) st->backp)
146 	       & (__alignof__ (struct Ebl_Strent) - 1)))
147 	   & (__alignof__ (struct Ebl_Strent) - 1));
148 
149   /* Make sure there is enough room in the memory block.  */
150   if (st->left < align + sizeof (struct Ebl_Strent) + len)
151     {
152       if (morememory (st, sizeof (struct Ebl_Strent) + len))
153 	return NULL;
154 
155       align = 0;
156     }
157 
158   /* Create the reserved string.  */
159   newstr = (struct Ebl_Strent *) (st->backp + align);
160   newstr->string = str;
161   newstr->len = len;
162   newstr->next = NULL;
163   newstr->left = NULL;
164   newstr->right = NULL;
165   newstr->offset = 0;
166   for (i = len - 2; i >= 0; --i)
167     newstr->reverse[i] = str[len - 2 - i];
168   newstr->reverse[len - 1] = '\0';
169   st->backp += align + sizeof (struct Ebl_Strent) + len;
170   st->left -= align + sizeof (struct Ebl_Strent) + len;
171 
172   return newstr;
173 }
174 
175 
176 /* XXX This function should definitely be rewritten to use a balancing
177    tree algorith (AVL, red-black trees).  For now a simple, correct
178    implementation is enough.  */
179 static struct Ebl_Strent **
searchstring(struct Ebl_Strent ** sep,struct Ebl_Strent * newstr)180 searchstring (struct Ebl_Strent **sep, struct Ebl_Strent *newstr)
181 {
182   int cmpres;
183 
184   /* More strings?  */
185   if (*sep == NULL)
186     {
187       *sep = newstr;
188       return sep;
189     }
190 
191   /* Compare the strings.  */
192   cmpres = memcmp ((*sep)->reverse, newstr->reverse,
193 		   MIN ((*sep)->len, newstr->len) - 1);
194   if (cmpres == 0)
195     /* We found a matching string.  */
196     return sep;
197   else if (cmpres > 0)
198     return searchstring (&(*sep)->left, newstr);
199   else
200     return searchstring (&(*sep)->right, newstr);
201 }
202 
203 
204 /* Add new string.  The actual string is assumed to be permanent.  */
205 struct Ebl_Strent *
ebl_strtabadd(struct Ebl_Strtab * st,const char * str,size_t len)206 ebl_strtabadd (struct Ebl_Strtab *st, const char *str, size_t len)
207 {
208   struct Ebl_Strent *newstr;
209   struct Ebl_Strent **sep;
210 
211   /* Compute the string length if the caller doesn't know it.  */
212   if (len == 0)
213     len = strlen (str) + 1;
214 
215   /* Make sure all "" strings get offset 0 but only if the table was
216      created with a special null entry in mind.  */
217   if (len == 1 && st->null.string != NULL)
218     return &st->null;
219 
220   /* Allocate memory for the new string and its associated information.  */
221   newstr = newstring (st, str, len);
222   if (newstr == NULL)
223     return NULL;
224 
225   /* Search in the array for the place to insert the string.  If there
226      is no string with matching prefix and no string with matching
227      leading substring, create a new entry.  */
228   sep = searchstring (&st->root, newstr);
229   if (*sep != newstr)
230     {
231       /* This is not the same entry.  This means we have a prefix match.  */
232       if ((*sep)->len > newstr->len)
233 	{
234 	  struct Ebl_Strent *subs;
235 
236 	  /* Check whether we already know this string.  */
237 	  for (subs = (*sep)->next; subs != NULL; subs = subs->next)
238 	    if (subs->len == newstr->len)
239 	      {
240 		/* We have an exact match with a substring.  Free the memory
241 		   we allocated.  */
242 		st->left += st->backp - (char *) newstr;
243 		st->backp = (char *) newstr;
244 
245 		return subs;
246 	      }
247 
248 	  /* We have a new substring.  This means we don't need the reverse
249 	     string of this entry anymore.  */
250 	  st->backp -= newstr->len;
251 	  st->left += newstr->len;
252 
253 	  newstr->next = (*sep)->next;
254 	  (*sep)->next = newstr;
255 	}
256       else if ((*sep)->len != newstr->len)
257 	{
258 	  /* When we get here it means that the string we are about to
259 	     add has a common prefix with a string we already have but
260 	     it is longer.  In this case we have to put it first.  */
261 	  st->total += newstr->len - (*sep)->len;
262 	  newstr->next = *sep;
263 	  newstr->left = (*sep)->left;
264 	  newstr->right = (*sep)->right;
265 	  *sep = newstr;
266 	}
267       else
268 	{
269 	  /* We have an exact match.  Free the memory we allocated.  */
270 	  st->left += st->backp - (char *) newstr;
271 	  st->backp = (char *) newstr;
272 
273 	  newstr = *sep;
274 	}
275     }
276   else
277     st->total += newstr->len;
278 
279   return newstr;
280 }
281 
282 
283 static void
copystrings(struct Ebl_Strent * nodep,char ** freep,size_t * offsetp)284 copystrings (struct Ebl_Strent *nodep, char **freep, size_t *offsetp)
285 {
286   struct Ebl_Strent *subs;
287 
288   if (nodep->left != NULL)
289     copystrings (nodep->left, freep, offsetp);
290 
291   /* Process the current node.  */
292   nodep->offset = *offsetp;
293   *freep = (char *) mempcpy (*freep, nodep->string, nodep->len);
294   *offsetp += nodep->len;
295 
296   for (subs = nodep->next; subs != NULL; subs = subs->next)
297     {
298       assert (subs->len < nodep->len);
299       subs->offset = nodep->offset + nodep->len - subs->len;
300       assert (subs->offset != 0 || subs->string[0] == '\0');
301     }
302 
303   if (nodep->right != NULL)
304     copystrings (nodep->right, freep, offsetp);
305 }
306 
307 
308 void
ebl_strtabfinalize(struct Ebl_Strtab * st,Elf_Data * data)309 ebl_strtabfinalize (struct Ebl_Strtab *st, Elf_Data *data)
310 {
311   size_t copylen;
312   char *endp;
313   size_t nulllen = st->nullstr ? 1 : 0;
314 
315   /* Fill in the information.  */
316   data->d_buf = malloc (st->total + nulllen);
317   if (data->d_buf == NULL)
318     abort ();
319 
320   /* The first byte must always be zero if we created the table with a
321      null string.  */
322   if (st->nullstr)
323     *((char *) data->d_buf) = '\0';
324 
325   data->d_type = ELF_T_BYTE;
326   data->d_size = st->total + nulllen;
327   data->d_off = 0;
328   data->d_align = 1;
329   data->d_version = EV_CURRENT;
330 
331   /* Now run through the tree and add all the string while also updating
332      the offset members of the elfstrent records.  */
333   endp = (char *) data->d_buf + nulllen;
334   copylen = nulllen;
335   copystrings (st->root, &endp, &copylen);
336   assert (copylen == st->total + nulllen);
337 }
338 
339 
340 size_t
ebl_strtaboffset(struct Ebl_Strent * se)341 ebl_strtaboffset (struct Ebl_Strent *se)
342 {
343   return se->offset;
344 }
345 
346 
347 const char *
ebl_string(struct Ebl_Strent * se)348 ebl_string (struct Ebl_Strent *se)
349 {
350   assert (se->string != NULL);
351 
352   return se->string;
353 }
354