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1 /*
2 * Copyright 2006 Sony Computer Entertainment Inc.
3 *
4 * Licensed under the MIT Open Source License, for details please see license.txt or the website
5 * http://www.opensource.org/licenses/mit-license.php
6 *
7 */
8 
9 #include <dae/daeMetaChoice.h>
10 #include <dae/daeMetaElement.h>
11 
daeMetaChoice(daeMetaElement * container,daeMetaCMPolicy * parent,daeUInt choiceNum,daeUInt ordinal,daeInt minO,daeInt maxO)12 daeMetaChoice::daeMetaChoice( daeMetaElement *container, daeMetaCMPolicy *parent, daeUInt choiceNum, daeUInt ordinal,
13 												 daeInt minO, daeInt maxO) : daeMetaCMPolicy( container, parent, ordinal, minO, maxO ), _choiceNum(choiceNum)
14 {}
15 
~daeMetaChoice()16 daeMetaChoice::~daeMetaChoice()
17 {}
18 
placeElement(daeElement * parent,daeElement * child,daeUInt & ordinal,daeInt offset,daeElement * before,daeElement * after)19 daeElement *daeMetaChoice::placeElement( daeElement *parent, daeElement *child, daeUInt &ordinal, daeInt offset, daeElement* before, daeElement *after ) {
20 	(void)offset;
21 	if ( _maxOccurs == -1 ) {
22 		//Needed to prevent infinate loops. If unbounded check to see if you have the child before just trying to place
23 		if ( findChild( child->getElementName() ) == NULL ) {
24 			return NULL;
25 		}
26 	}
27 
28 	daeElement *retVal = NULL;
29 
30 	daeTArray< daeCharArray *> *CMData = (daeTArray< daeCharArray *>*)_container->getMetaCMData()->getWritableMemory(parent);
31 	daeCharArray *myData = CMData->get( _choiceNum );
32 	size_t count = myData->getCount();
33 
34 	for ( daeInt i = 0; ( i < _maxOccurs || _maxOccurs == -1 ); i++ )
35 	{
36 		if ( (daeInt) count > i && myData->get(i) != -1 ) //choice has already been made
37 		{
38 			if ( _children[ myData->get(i) ]->placeElement( parent, child, ordinal, i, before, after ) != NULL )
39 			{
40 				retVal = child;
41 				ordinal = ordinal  + _ordinalOffset;
42 				break;
43 			}
44 			//else //try to see if everything can be in a different choice
45 			//{
46 			//	daeElementRefArray childsInChoice;
47 			//	_children[ myData->get(i) ]->getChildren( parent, childsInChoice );
48 			//	for ( size_t x = myData->get(i) +1; x < cnt; x++ )
49 			//	{
50 			//		daeElementRefArray childsInNext;
51 			//		_children[ x ]->getChildren( parent, childsInNext ); //If you get children in another choice then
52 			//		//both choices can have the same type of children.
53 			//		if ( childsInNext.getCount() == childsInChoice.getCount() )
54 			//		{
55 			//			//if there are the same ammount of children then all present children can belong to both
56 			//			//choices. Try to place the new child in this next choice.
57 			//			if ( _children[x]->placeElement( parent, child, ordinal, i, before, after ) != NULL )
58 			//			{
59 			//				retVal = child;
60 			//				ordinal = ordinal  + _ordinalOffset;
61 
62 			//				myData->set( i, (daeChar)x ); //change the choice to this new one
63 			//				break;
64 			//			}
65 			//		}
66 			//	}
67 			//	if ( retVal != NULL ) break;
68 			//}
69 		}
70 		else //no choice has been made yet
71 		{
72 			size_t cnt = _children.getCount();
73 			for ( size_t x = 0; x < cnt; x++ )
74 			{
75 				if ( _children[x]->placeElement( parent, child, ordinal, i, before, after ) != NULL )
76 				{
77 					retVal = child;
78 					ordinal = ordinal  + _ordinalOffset;
79 
80 					myData->append( (daeChar)x ); //you always place in the next available choice up to maxOccurs
81 					count ++;
82 					break;
83 				}
84 			}
85 			if ( retVal != NULL ) break;
86 		}
87 	}
88 	if ( retVal == NULL )
89 	{
90 		if ( findChild( child->getElementName() ) == NULL ) {
91 			return NULL;
92 		}
93 		for ( daeInt i = 0; ( i < _maxOccurs || _maxOccurs == -1 ); i++ )
94 		{
95 			daeElementRefArray childsInChoice;
96 			_children[ myData->get(i) ]->getChildren( parent, childsInChoice );
97 			size_t cnt = _children.getCount();
98 			for ( size_t x = myData->get(i) +1; x < cnt; x++ )
99 			{
100 				daeElementRefArray childsInNext;
101 				_children[ x ]->getChildren( parent, childsInNext ); //If you get children in another choice then
102 				//both choices can have the same type of children.
103 				if ( childsInNext.getCount() == childsInChoice.getCount() )
104 				{
105 					//if there are the same ammount of children then all present children can belong to both
106 					//choices. Try to place the new child in this next choice.
107 					if ( _children[x]->placeElement( parent, child, ordinal, i, before, after ) != NULL )
108 					{
109 						retVal = child;
110 						ordinal = ordinal  + _ordinalOffset;
111 
112 						myData->set( i, (daeChar)x ); //change the choice to this new one
113 						break;
114 					}
115 				}
116 			}
117 			if ( retVal != NULL ) break;
118 		}
119 	}
120 	return retVal;
121 }
122 
removeElement(daeElement * parent,daeElement * child)123 daeBool daeMetaChoice::removeElement( daeElement *parent, daeElement *child ) {
124 	size_t cnt = _children.getCount();
125 	for ( size_t x = 0; x < cnt; x++ ) {
126 		if ( _children[x]->removeElement( parent, child ) ) {
127 			return true;
128 		}
129 	}
130 	return false;
131 }
132 
findChild(daeString elementName)133 daeMetaElement * daeMetaChoice::findChild( daeString elementName ) {
134 	daeMetaElement *me = NULL;
135 	size_t cnt = _children.getCount();
136 	for ( size_t x = 0; x < cnt; x++ ) {
137 		me = _children[x]->findChild( elementName );
138 		if ( me != NULL ) {
139 			return me;
140 		}
141 	}
142 	return NULL;
143 }
144 
getChildren(daeElement * parent,daeElementRefArray & array)145 void daeMetaChoice::getChildren( daeElement *parent, daeElementRefArray &array ) {
146 	size_t cnt = _children.getCount();
147 	for ( size_t x = 0; x < cnt; x++ ) {
148 		_children[x]->getChildren( parent, array );
149 	}
150 }
151 
152