Searched refs:partitions_per_word (Results 1 – 1 of 1) sorted by relevance
110 int partitions_per_word=phrasebook->dim; in res_inverse() local120 int partwords=(partvals+partitions_per_word-1)/partitions_per_word; in res_inverse()131 partword[j]=(char *)alloca(partwords*partitions_per_word* in res_inverse()140 partword[0][i+partitions_per_word-1]=1; in res_inverse()141 for(k=partitions_per_word-2;k>=0;k--) in res_inverse()145 for(k=partitions_per_word-1;k>=0;k--) in res_inverse()154 for(k=0;k<partitions_per_word;k++){ in res_inverse()164 for(k=0;k<partitions_per_word && i<partvals;k++,i++) in res_inverse()192 int partwords=(partvals+partitions_per_word-1)/partitions_per_word; in res_inverse()195 (char *)alloca(partwords*partitions_per_word*sizeof(*partword)); in res_inverse()[all …]