Lines Matching refs:number
434 /* Compute the minimum number of offsets that we need to reset each time. Doing
461 /* First, ensure the minimum number of matches are present. */
462 /* First, ensure the minimum number of matches are present. Use inline
463 /* First, ensure the minimum number of matches are present. We get back
468 /* For extended extraction brackets (large number), we have to fish out
469 /* For extended extraction brackets (large number), we have to fish out the
517 /* Reset the maximum number of extractions we might see. */
523 /* Skip over conditional reference data or large extraction number data if
577 DPRINTF (("bracket %d failed\n", number));
599 Returns: > 0 => success; value is the number of elements filled in
1063 group number back at the start and if necessary complete handling an
1242 if (number > 0)
1243 if (number > EXTRACT_BASIC_MAX)
1244 if (number > EXTRACT_BASIC_MAX)
1293 int number = *prev - OP_BRA;
1294 int number = op - OP_BRA;
1295 int offset = (ecode[1] << 9) | (ecode[2] << 1); /* Doubled reference number */
1296 int offset = (ecode[4] << 9) | (ecode[5] << 1); /* Doubled reference number */
1310 int save_offset3 = md->offset_vector[md->offset_end - number];
1316 it as matched, any number of times (otherwise there could be infinite
1323 length number to print
1389 maximum. Alternatively, if maximizing, find the maximum number of
1390 maximum. Alternatively, if maximizing, find the maximum number of
1403 md->offset_vector[md->offset_end - number] = eptr - md->start_subject;
1404 md->offset_vector[md->offset_end - number] = save_offset3;
1405 md->offset_vector[md->offset_end - number];
1438 minimum number of matches are present. If min = max, continue at the same
1439 minimum number of matches are present. If min = max, continue at the same
1452 number = (ecode[4] << 8) | ecode[5];
1453 number = (prev[4] << 8) | prev[5];
1454 number from a dummy opcode at the start. */
1455 number, then move along the subject till after the recursive match,
1462 offset = number << 1;
1463 offset = number << 1;
1470 offsetcount the number of elements in the vector
1509 printf ("end bracket %d", number);
1514 printf ("start bracket %d subject=", number);
1532 repeat limits are compiled as a number of copies, with the optional ones
1710 than the number of characters left in the string, so the match fails.
1726 the minimum number of bytes before we start. */
1727 the number from a dummy opcode at the start. */
1750 up quickly if there are fewer than the minimum number of characters left in
1751 up quickly if there are fewer than the minimum number of characters left in