Searched refs:nextWordPosition (Results 1 – 8 of 8) sorted by relevance
44 VisiblePosition nextWordPosition(const VisiblePosition &);
310 VisiblePosition nextWordPosition(const VisiblePosition &c) in nextWordPosition() function1240 VisiblePosition wordBreak = nextWordPosition(boundaryPosition); in lastWordBreakInBox()1276 wordBreak = nextWordPosition(wordBreak); in nextWordBreakInBoxInsideBlockWithDifferentDirectionality()1441 VisiblePosition positionAfterCurrentWord = nextWordPosition(position); in positionBeforeNextWord()1442 VisiblePosition positionAfterNextWord = nextWordPosition(positionAfterCurrentWord); in positionBeforeNextWord()1454 return nextWordPosition(positionBeforePreviousWord); in positionAfterPreviousWord()1483 wordBreak = nextWordPosition(visiblePosition); in leftWordPosition()1524 wordBreak = nextWordPosition(visiblePosition); in rightWordPosition()
435 pos = nextWordPosition(pos); in modifyExtendingRight()468 pos = nextWordPosition(pos); in modifyExtendingForward()547 pos = nextWordPosition(VisiblePosition(m_selection.extent(), m_selection.affinity())); in modifyMovingForward()605 pos = nextWordPosition(pos); in modifyExtendingLeft()
2408 startOfFirstWord = nextWordPosition(startOfFirstWord); in updateMarkersForWordsAffectedByEditing()
15730 or nextWordPosition based on the directionality of the box. If this word break position 15731 is also inside the same box, return it. Otherwise (the nextWordPosition or 15746 previousWordPosition() and nextWordPosition(). So when box directionality is the same as 15753 we cannot simply return nextWordPosition() because it would return the right boundary15754 … of a word. Instead, we return nextWordPosition()'s nextWordPosition()'s previousWordPosition().19505 or nextWordPosition based on the directionality of the box. If this word break position 19506 is also inside the same box, return it. Otherwise (the nextWordPosition or 19521 previousWordPosition() and nextWordPosition(). So when box directionality is the same as 19528 we cannot simply return nextWordPosition() because it would return the right boundary19529 … of a word. Instead, we return nextWordPosition()'s nextWordPosition()'s previousWordPosition().
26840 (khtml::nextWordPosition):35540 (DOM::nextWordPosition): Added.35774 (DOM::Position::nextWordPosition): Ditto.38953 (DOM::Position::nextWordPosition): Ditto.38962 I have implemented versions of previousWordPosition and nextWordPosition that are now38988 (DOM::Position::nextWordPosition): Ditto39672 (DOM::Position::nextWordPosition): Ditto.43081 (DOM::Position::nextWordPosition): Ditto.46597 (DOMPosition::nextWordPosition): Added.
6981 (WebCore::nextWordPosition):8412 (WebCore::nextWordPosition):8504 (WebCore::nextWordPosition): Ditto.9585 (WebCore::nextWordPosition):
17208 (WebCore::nextWordPosition):