#!/usr/bin/python # (C) Copyright IBM Corp. 2006 # Author: Dustin Kirkland # Description: # Input: Two or more files containing results from different executions of # the LTP. The input can either be file names or the url location # of the ltp.results file. # Output: A report on the following: # - The total number of tests executed in each run # - The testname, sequence number, and output of each run # where the results of those runs differ # Return: # 0 if all runs had identical results # Non-zero if results differ, or bad input import sys, string, re from autotest_lib.client.common_lib import utils def usage(): print "\nUsage: \n\ ltp-diff results1 results2 ... locationN \n\ Note: location[1,2,N] may be local files or URLs of LTP results\n" sys.exit(1) def get_results(results_files): """ Download the results if needed. Return results of each run in a numerically-indexed dictionary of dictionaries keyed on testnames. Return dictionary keyed on unique testnames across all runs. """ r = re.compile('(\S+\s+\S+)\s+(\S+)\s+:') i = 0 runs = {} testnames = {} for file in results_files: runs[i] = {} try: fh = utils.urlopen(file) results = fh.readlines() fh.close() except: print "ERROR: reading results resource [%s]" % (file) usage() for line in results: try: s = r.match(line) testname = s.group(1) status = s.group(2) runs[i][testname] = status testnames[testname] = 1 except: pass i += 1 return (runs, testnames) def compare_results(runs): """ Loop through all testnames alpahbetically. Print any testnames with differing results across runs. Return 1 if any test results across runs differ. Return 0 if all test results match. """ rc = 0 print "LTP Test Results to Compare" for i in range(len(runs)): print " Run[%d]: %d" % (i, len(runs[i].keys())) print "" header = 0 all_testnames = testnames.keys() all_testnames.sort() for testname in all_testnames: differ = 0 for i in range(1,len(runs)): # Must handle testcases that executed in one run # but not another by setting status to "null" if not runs[i].has_key(testname): runs[i][testname] = "null" if not runs[i-1].has_key(testname): runs[i-1][testname] = "null" # Check for the results inconsistencies if runs[i][testname] != runs[i-1][testname]: differ = 1 if differ: if header == 0: # Print the differences header only once print "Tests with Inconsistent Results across Runs" print " %-35s:\t%s" % ("Testname,Sequence", "Run Results") header = 1 # Print info if results differ rc = 1 testname_cleaned = re.sub('\s+', ',', testname) print " %-35s:\t" % (testname_cleaned), all_results = "" for i in range(len(runs)): all_results += runs[i][testname] if i+1