Searched refs:kFullFontName (Results 1 – 2 of 2) sorted by relevance
55 case NameId::kFullFontName: in ConstructName()81 if (name_id == NameId::kFullFontName) { in HashCode()112 case NameId::kFullFontName: in HasName()
45 kFullFontName = 4, enumerator