Searched refs:Freq (Results 1 – 2 of 2) sorted by relevance
279 for (n = 0; n < L_CODES; n++) s->dyn_ltree[n].Freq = 0; in init_block()280 for (n = 0; n < D_CODES; n++) s->dyn_dtree[n].Freq = 0; in init_block()281 for (n = 0; n < BL_CODES; n++) s->bl_tree[n].Freq = 0; in init_block()283 s->dyn_ltree[END_BLOCK].Freq = 1; in init_block()308 (tree[n].Freq < tree[m].Freq || \309 (tree[n].Freq == tree[m].Freq && depth[n] <= depth[m]))390 f = tree[n].Freq; in gen_bitlen()425 *(long)tree[m].Freq; in gen_bitlen()503 if (tree[n].Freq != 0) { in build_tree()518 tree[node].Freq = 1; in build_tree()[all …]
53 #define Freq fc.freq macro