1 /*
2 * Copyright (c) 2013-2019 Huawei Technologies Co., Ltd. All rights reserved.
3 * Copyright (c) 2020-2021 Huawei Device Co., Ltd. All rights reserved.
4 *
5 * Redistribution and use in source and binary forms, with or without modification,
6 * are permitted provided that the following conditions are met:
7 *
8 * 1. Redistributions of source code must retain the above copyright notice, this list of
9 * conditions and the following disclaimer.
10 *
11 * 2. Redistributions in binary form must reproduce the above copyright notice, this list
12 * of conditions and the following disclaimer in the documentation and/or other materials
13 * provided with the distribution.
14 *
15 * 3. Neither the name of the copyright holder nor the names of its contributors may be used
16 * to endorse or promote products derived from this software without specific prior written
17 * permission.
18 *
19 * THIS SOFTWARE IS PROVIDED BY THE COPYRIGHT HOLDERS AND CONTRIBUTORS
20 * "AS IS" AND ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO,
21 * THE IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR
22 * PURPOSE ARE DISCLAIMED. IN NO EVENT SHALL THE COPYRIGHT HOLDER OR
23 * CONTRIBUTORS BE LIABLE FOR ANY DIRECT, INDIRECT, INCIDENTAL, SPECIAL,
24 * EXEMPLARY, OR CONSEQUENTIAL DAMAGES (INCLUDING, BUT NOT LIMITED TO,
25 * PROCUREMENT OF SUBSTITUTE GOODS OR SERVICES; LOSS OF USE, DATA, OR PROFITS;
26 * OR BUSINESS INTERRUPTION) HOWEVER CAUSED AND ON ANY THEORY OF LIABILITY,
27 * WHETHER IN CONTRACT, STRICT LIABILITY, OR TORT (INCLUDING NEGLIGENCE OR
28 * OTHERWISE) ARISING IN ANY WAY OUT OF THE USE OF THIS SOFTWARE, EVEN IF
29 * ADVISED OF THE POSSIBILITY OF SUCH DAMAGE.
30 */
31 #include "It_posix_pthread.h"
32
PthreadOnceF01(VOID)33 static VOID PthreadOnceF01(VOID)
34 {
35 g_testCount++;
36 }
Testcase(VOID)37 static UINT32 Testcase(VOID)
38 {
39 UINT32 ret;
40 pthread_once_t onceBlock = PTHREAD_ONCE_INIT;
41
42 g_testCount = 0;
43
44 // pthread_once_init: (0) NEVER (1) IN_PROGRESS (2) DONE
45 // If 1:all pthread_once() will wait until one of them transfer his state to (2) DONE,so all of them will stuck
46 // infinitely. We can't make it happen that all pthreads stuck infinitely in testsuit which is unreasonable.
47 onceBlock = 2;
48 ret = pthread_once(&onceBlock, PthreadOnceF01);
49 ICUNIT_ASSERT_EQUAL(ret, 0, ret);
50 ICUNIT_ASSERT_EQUAL(g_testCount, 0, g_testCount);
51
52 onceBlock = PTHREAD_ONCE_INIT;
53
54 ret = pthread_once(&onceBlock, PthreadOnceF01);
55 ICUNIT_ASSERT_EQUAL(ret, 0, ret);
56 ICUNIT_ASSERT_EQUAL(g_testCount, 1, g_testCount);
57
58 ret = pthread_once(&onceBlock, PthreadOnceF01);
59 ICUNIT_ASSERT_EQUAL(onceBlock, 2, onceBlock);
60 ICUNIT_ASSERT_EQUAL(ret, 0, ret);
61 ICUNIT_ASSERT_EQUAL(g_testCount, 1, g_testCount);
62
63 return PTHREAD_NO_ERROR;
64 }
65
ItPosixPthread019(VOID)66 VOID ItPosixPthread019(VOID) // IT_Layer_ModuleORFeature_No
67 {
68 TEST_ADD_CASE("IT_POSIX_PTHREAD_019", Testcase, TEST_POSIX, TEST_PTHREAD, TEST_LEVEL0, TEST_FUNCTION);
69 }
70