1 # Copyright JS Foundation and other contributors, http://js.foundation 2 # 3 # Licensed under the Apache License, Version 2.0 (the "License"); 4 # you may not use this file except in compliance with the License. 5 # You may obtain a copy of the License at 6 # 7 # http://www.apache.org/licenses/LICENSE-2.0 8 # 9 # Unless required by applicable law or agreed to in writing, software 10 # distributed under the License is distributed on an "AS IS" BASIS 11 # WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. 12 # See the License for the specific language governing permissions and 13 # limitations under the License. 14 15 16 LICENSE = """/* Copyright JS Foundation and other contributors, http://js.foundation 17 * 18 * Licensed under the Apache License, Version 2.0 (the "License"); 19 * you may not use this file except in compliance with the License. 20 * You may obtain a copy of the License at 21 * 22 * http://www.apache.org/licenses/LICENSE-2.0 23 * 24 * Unless required by applicable law or agreed to in writing, software 25 * distributed under the License is distributed on an "AS IS" BASIS 26 * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. 27 * See the License for the specific language governing permissions and 28 * limitations under the License. 29 */""" 30 31 32 def format_code(code, indent, digit_number=4): 33 def regroup(list_to_group, num): 34 return [list_to_group[i:i+num] for i in range(0, len(list_to_group), num)] 35 36 def hex_format(char, digit_number): 37 if isinstance(char, str): 38 char = ord(char) 39 40 return ("0x{:0%sx}" % digit_number).format(char) 41 42 lines = [] 43 44 nums_per_line = 10 45 width = nums_per_line * (digit_number + 4) 46 # convert all characters to hex format 47 converted_code = [hex_format(char, digit_number) for char in code] 48 # 10 hex number per line 49 for line in regroup(", ".join(converted_code), width): 50 lines.append((' ' * indent) + line.strip()) 51 return "\n".join(lines) 52