1 #include "time_impl.h"
2 #include <limits.h>
3
4 /* 2000-03-01 (mod 400 year, immediately after feb29 */
5 #define LEAPOCH (946684800LL + 86400*(31+29))
6
7 #define DAYS_PER_400Y (365*400 + 97)
8 #define DAYS_PER_100Y (365*100 + 24)
9 #define DAYS_PER_4Y (365*4 + 1)
10
__secs_to_tm(long long t,struct tm * tm)11 int __secs_to_tm(long long t, struct tm *tm)
12 {
13 long long days, secs, years;
14 int remdays, remsecs, remyears;
15 int qc_cycles, c_cycles, q_cycles;
16 int months;
17 int wday, yday, leap;
18 static const char days_in_month[] = {31,30,31,30,31,31,30,31,30,31,31,29};
19
20 /* Reject time_t values whose year would overflow int */
21 if (t < INT_MIN * 31622400LL || t > INT_MAX * 31622400LL)
22 return -1;
23
24 secs = t - LEAPOCH;
25 days = secs / 86400;
26 remsecs = secs % 86400;
27 if (remsecs < 0) {
28 remsecs += 86400;
29 days--;
30 }
31
32 wday = (3+days)%7;
33 if (wday < 0) wday += 7;
34
35 qc_cycles = days / DAYS_PER_400Y;
36 remdays = days % DAYS_PER_400Y;
37 if (remdays < 0) {
38 remdays += DAYS_PER_400Y;
39 qc_cycles--;
40 }
41
42 c_cycles = remdays / DAYS_PER_100Y;
43 if (c_cycles == 4) c_cycles--;
44 remdays -= c_cycles * DAYS_PER_100Y;
45
46 q_cycles = remdays / DAYS_PER_4Y;
47 if (q_cycles == 25) q_cycles--;
48 remdays -= q_cycles * DAYS_PER_4Y;
49
50 remyears = remdays / 365;
51 if (remyears == 4) remyears--;
52 remdays -= remyears * 365;
53
54 leap = !remyears && (q_cycles || !c_cycles);
55 yday = remdays + 31 + 28 + leap;
56 if (yday >= 365+leap) yday -= 365+leap;
57
58 years = remyears + 4*q_cycles + 100*c_cycles + 400LL*qc_cycles;
59
60 for (months=0; days_in_month[months] <= remdays; months++)
61 remdays -= days_in_month[months];
62
63 if (months >= 10) {
64 months -= 12;
65 years++;
66 }
67
68 if (years+100 > INT_MAX || years+100 < INT_MIN)
69 return -1;
70
71 tm->tm_year = years + 100;
72 tm->tm_mon = months + 2;
73 tm->tm_mday = remdays + 1;
74 tm->tm_wday = wday;
75 tm->tm_yday = yday;
76
77 tm->tm_hour = remsecs / 3600;
78 tm->tm_min = remsecs / 60 % 60;
79 tm->tm_sec = remsecs % 60;
80
81 return 0;
82 }
83