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1; RUN: opt < %s -instsimplify
2
3; The mul can be proved to always overflow (turning a negative value
4; into a positive one) and thus results in undefined behaviour.  At
5; the same time we were deducing from the nsw flag that that mul could
6; be assumed to have a negative value (since if not it has an undefined
7; value, which can be taken to be negative).  We were reporting the mul
8; as being both positive and negative, firing an assertion!
9define i1 @test1(i32 %a) {
10entry:
11  %0 = or i32 %a, 1
12  %1 = shl i32 %0, 31
13  %2 = mul nsw i32 %1, 4
14  %3 = and i32 %2, -4
15  %4 = icmp ne i32 %3, 0
16  ret i1 %4
17}
18