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1 ///////////////////////////////////////////////////////////////////////////
2 //
3 // Copyright (c) 2002, Industrial Light & Magic, a division of Lucas
4 // Digital Ltd. LLC
5 //
6 // All rights reserved.
7 //
8 // Redistribution and use in source and binary forms, with or without
9 // modification, are permitted provided that the following conditions are
10 // met:
11 // *       Redistributions of source code must retain the above copyright
12 // notice, this list of conditions and the following disclaimer.
13 // *       Redistributions in binary form must reproduce the above
14 // copyright notice, this list of conditions and the following disclaimer
15 // in the documentation and/or other materials provided with the
16 // distribution.
17 // *       Neither the name of Industrial Light & Magic nor the names of
18 // its contributors may be used to endorse or promote products derived
19 // from this software without specific prior written permission.
20 //
21 // THIS SOFTWARE IS PROVIDED BY THE COPYRIGHT HOLDERS AND CONTRIBUTORS
22 // "AS IS" AND ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT
23 // LIMITED TO, THE IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR
24 // A PARTICULAR PURPOSE ARE DISCLAIMED. IN NO EVENT SHALL THE COPYRIGHT
25 // OWNER OR CONTRIBUTORS BE LIABLE FOR ANY DIRECT, INDIRECT, INCIDENTAL,
26 // SPECIAL, EXEMPLARY, OR CONSEQUENTIAL DAMAGES (INCLUDING, BUT NOT
27 // LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS OR SERVICES; LOSS OF USE,
28 // DATA, OR PROFITS; OR BUSINESS INTERRUPTION) HOWEVER CAUSED AND ON ANY
29 // THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT LIABILITY, OR TORT
30 // (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY OUT OF THE USE
31 // OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF SUCH DAMAGE.
32 //
33 ///////////////////////////////////////////////////////////////////////////
34 
35 // Primary authors:
36 //     Florian Kainz <kainz@ilm.com>
37 //     Rod Bogart <rgb@ilm.com>
38 
39 
40 //---------------------------------------------------------------------------
41 //
42 //	class half --
43 //	implementation of non-inline members
44 //
45 //---------------------------------------------------------------------------
46 
47 #include <assert.h>
48 #include "half.h"
49 
50 using namespace std;
51 
52 //-------------------------------------------------------------
53 // Lookup tables for half-to-float and float-to-half conversion
54 //-------------------------------------------------------------
55 
56 HALF_EXPORT_CONST half::uif half::_toFloat[1 << 16] =
57 #include "toFloat.h"
58 HALF_EXPORT_CONST unsigned short half::_eLut[1 << 9] =
59 #include "eLut.h"
60 
61 
62 //-----------------------------------------------
63 // Overflow handler for float-to-half conversion;
64 // generates a hardware floating-point overflow,
65 // which may be trapped by the operating system.
66 //-----------------------------------------------
67 
68 float
69 half::overflow ()
70 {
71     volatile float f = 1e10;
72 
73     for (int i = 0; i < 10; i++)
74     f *= f;				// this will overflow before
75                     // the for�loop terminates
76     return f;
77 }
78 
79 
80 //-----------------------------------------------------
81 // Float-to-half conversion -- general case, including
82 // zeroes, denormalized numbers and exponent overflows.
83 //-----------------------------------------------------
84 
85 short
convert(int i)86 half::convert (int i)
87 {
88     //
89     // Our floating point number, f, is represented by the bit
90     // pattern in integer i.  Disassemble that bit pattern into
91     // the sign, s, the exponent, e, and the significand, m.
92     // Shift s into the position where it will go in in the
93     // resulting half number.
94     // Adjust e, accounting for the different exponent bias
95     // of float and half (127 versus 15).
96     //
97 
98     register int s =  (i >> 16) & 0x00008000;
99     register int e = ((i >> 23) & 0x000000ff) - (127 - 15);
100     register int m =   i        & 0x007fffff;
101 
102     //
103     // Now reassemble s, e and m into a half:
104     //
105 
106     if (e <= 0)
107     {
108     if (e < -10)
109     {
110         //
111         // E is less than -10.  The absolute value of f is
112         // less than HALF_MIN (f may be a small normalized
113         // float, a denormalized float or a zero).
114         //
115         // We convert f to a half zero with the same sign as f.
116         //
117 
118         return s;
119     }
120 
121     //
122     // E is between -10 and 0.  F is a normalized float
123     // whose magnitude is less than HALF_NRM_MIN.
124     //
125     // We convert f to a denormalized half.
126     //
127 
128     //
129     // Add an explicit leading 1 to the significand.
130     //
131 
132     m = m | 0x00800000;
133 
134     //
135     // Round to m to the nearest (10+e)-bit value (with e between
136     // -10 and 0); in case of a tie, round to the nearest even value.
137     //
138     // Rounding may cause the significand to overflow and make
139     // our number normalized.  Because of the way a half's bits
140     // are laid out, we don't have to treat this case separately;
141     // the code below will handle it correctly.
142     //
143 
144     int t = 14 - e;
145     int a = (1 << (t - 1)) - 1;
146     int b = (m >> t) & 1;
147 
148     m = (m + a + b) >> t;
149 
150     //
151     // Assemble the half from s, e (zero) and m.
152     //
153 
154     return s | m;
155     }
156     else if (e == 0xff - (127 - 15))
157     {
158     if (m == 0)
159     {
160         //
161         // F is an infinity; convert f to a half
162         // infinity with the same sign as f.
163         //
164 
165         return s | 0x7c00;
166     }
167     else
168     {
169         //
170         // F is a NAN; we produce a half NAN that preserves
171         // the sign bit and the 10 leftmost bits of the
172         // significand of f, with one exception: If the 10
173         // leftmost bits are all zero, the NAN would turn
174         // into an infinity, so we have to set at least one
175         // bit in the significand.
176         //
177 
178         m >>= 13;
179         return s | 0x7c00 | m | (m == 0);
180     }
181     }
182     else
183     {
184     //
185     // E is greater than zero.  F is a normalized float.
186     // We try to convert f to a normalized half.
187     //
188 
189     //
190     // Round to m to the nearest 10-bit value.  In case of
191     // a tie, round to the nearest even value.
192     //
193 
194     m = m + 0x00000fff + ((m >> 13) & 1);
195 
196     if (m & 0x00800000)
197     {
198         m =  0;		// overflow in significand,
199         e += 1;		// adjust exponent
200     }
201 
202     //
203     // Handle exponent overflow
204     //
205 
206     if (e > 30)
207     {
208         overflow ();	// Cause a hardware floating point overflow;
209         return s | 0x7c00;	// if this returns, the half becomes an
210     }   			// infinity with the same sign as f.
211 
212     //
213     // Assemble the half from s, e and m.
214     //
215 
216     return s | (e << 10) | (m >> 13);
217     }
218 }
219 
220 
221 //---------------------
222 // Stream I/O operators
223 //---------------------
224 
225 ostream &
operator <<(ostream & os,half h)226 operator << (ostream &os, half h)
227 {
228     os << float (h);
229     return os;
230 }
231 
232 
233 istream &
operator >>(istream & is,half & h)234 operator >> (istream &is, half &h)
235 {
236     float f;
237     is >> f;
238     h = half (f);
239     return is;
240 }
241 
242 
243 //---------------------------------------
244 // Functions to print the bit-layout of
245 // floats and halfs, mostly for debugging
246 //---------------------------------------
247 
248 void
printBits(ostream & os,half h)249 printBits (ostream &os, half h)
250 {
251     unsigned short b = h.bits();
252 
253     for (int i = 15; i >= 0; i--)
254     {
255     os << (((b >> i) & 1)? '1': '0');
256 
257     if (i == 15 || i == 10)
258         os << ' ';
259     }
260 }
261 
262 
263 void
printBits(ostream & os,float f)264 printBits (ostream &os, float f)
265 {
266     half::uif x;
267     x.f = f;
268 
269     for (int i = 31; i >= 0; i--)
270     {
271     os << (((x.i >> i) & 1)? '1': '0');
272 
273     if (i == 31 || i == 23)
274         os << ' ';
275     }
276 }
277 
278 
279 void
printBits(char c[19],half h)280 printBits (char c[19], half h)
281 {
282     unsigned short b = h.bits();
283 
284     for (int i = 15, j = 0; i >= 0; i--, j++)
285     {
286     c[j] = (((b >> i) & 1)? '1': '0');
287 
288     if (i == 15 || i == 10)
289         c[++j] = ' ';
290     }
291 
292     c[18] = 0;
293 }
294 
295 
296 void
printBits(char c[35],float f)297 printBits (char c[35], float f)
298 {
299     half::uif x;
300     x.f = f;
301 
302     for (int i = 31, j = 0; i >= 0; i--, j++)
303     {
304     c[j] = (((x.i >> i) & 1)? '1': '0');
305 
306     if (i == 31 || i == 23)
307         c[++j] = ' ';
308     }
309 
310     c[34] = 0;
311 }
312