• Home
  • Line#
  • Scopes#
  • Navigate#
  • Raw
  • Download
1 
2 #include <stdio.h>
3 #include <stdlib.h>
4 
5 // Do a test comparison.  By default memcheck does not use the
6 // expensive EQ/NE scheme as it would be too expensive.  The
7 // assignment to *hack is a trick to fool memcheck's bogus-literal
8 // spotter into thinking this is a bb which needs unusually careful
9 // attention, and therefore the expensive EQ/NE scheme is used.
10 
11 __attribute__((noinline)) // keep your grubby hands off this fn
foo(int * p1,int * p2,unsigned int * hack)12 void foo ( int* p1, int* p2, unsigned int * hack )
13 {
14   *hack = 0x80808080;
15   if (*p1 == *p2)
16     printf("foo\n");
17   else
18     printf("bar\n");
19 }
20 
21 static void bar ( void );
main(void)22 int main ( void )
23 {
24 
25   unsigned int hack;
26 
27   int* junk1 = malloc(sizeof(int));
28   int* junk2 = malloc(sizeof(int));
29 
30   short* ps1 = (short*)junk1;
31   short* ps2 = (short*)junk2;
32 
33   int*   pi1 = (int*)junk1;
34   int*   pi2 = (int*)junk2;
35   bar();
36   // both words completely undefined.  This should give an error.
37   foo(pi1,pi2, &hack);
38 
39   // set half of the words, but to different values; so this should
40   // not give an error, since inspection of the defined parts
41   // shows the two values are not equal, and so the definedness of
42   // the conclusion is unaffected by the undefined halves.
43   *ps1 = 41;
44   *ps2 = 42;
45   foo(pi1,pi2, &hack);
46 
47   // set half of the words, but to the same value, so this forces the
48   // result of the comparison to depend on the undefined halves.
49   // should give an error
50   *ps1 = 42;
51   *ps2 = 42;
52   foo(pi1,pi2, &hack);
53 
54   return 0;
55 }
56 
57 // Note: on ppc32/64 the second call to foo() does give an error,
58 // since the expensive EQ/NE scheme does not apply to the CmpORD
59 // primops used by ppc.
60 //
61 // On arm, the "normal" (x86-like) comparison primops are used, so
62 // the expensive EQ/NE scheme could apply.  However, it doesn't,
63 // because the constant 0x80808080 is placed in a constant pool
64 // and so never appears as a literal, and so the instrumenter
65 // never spots it and so doesn't use the expensive scheme (for foo).
66 // Hence also on ARM we get 3 errors, not 2.
67 //
68 // s390x is even more complicated: Depending on the architecture
69 // level we have the 0x80808080 either in the literal pool (3 errors)
70 // or with the extended immediate facility in an instruction (2 errors).
bar(void)71 static __attribute__((noinline)) void bar ( void )
72 {
73 #if defined(__powerpc__) || defined(__powerpc64__) || defined(__arm__)
74   fprintf(stderr, "Currently running on ppc32/64/arm: this test should give 3 errors, not 2.\n");
75 #endif
76 #if defined(__s390__)
77   fprintf(stderr, "On s390 we might see 2 or 3 errors.\n");
78 #endif
79 }
80