1 #include <stdint.h>
2 #include <stdio.h>
3 #include <string.h>
4
5 void
test(int32_t op1_init,int32_t op2_init,int32_t op3_init,int expected_cc)6 test(int32_t op1_init, int32_t op2_init, int32_t op3_init, int expected_cc)
7 {
8 register int32_t op1 asm("8") = op1_init;
9 register int32_t op3 asm("9") = op3_init;
10
11 int32_t op2 = op2_init;
12 int cc = 1 - expected_cc;
13
14 printf("before op1 = %#x\n", op1);
15 printf("before op2 = %#x\n", op2);
16 printf("before op3 = %#x\n", op3);
17
18 __asm__ volatile (
19 ".insn rsy,0xEB00000000f8, 8,9,%1\n\t"
20 "ipm %0\n\t"
21 "srl %0,28\n\t"
22 : "=d" (cc), "+Q" (op2), "+d"(op1), "+d"(op3)
23 :
24 : "cc");
25
26 printf("after op1 = %#x\n", op1);
27 printf("after op2 = %#x\n", op2);
28 printf("after op3 = %#x\n", op3);
29 printf("cc = %d\n", cc);
30
31 if (cc != expected_cc) {
32 printf("condition code is incorrect\n");
33 }
34 if (expected_cc == 0 && op2 != 0) {
35 printf("cc = 0, but result != 0\n");
36 }
37 if (expected_cc == 1 && op2 >= 0) {
38 printf("cc = 1, but result >= 0\n");
39 }
40 if (expected_cc == 2 && op2 <= 0) {
41 printf("cc = 2, but result <= 0\n");
42 }
43 /* the test for cc = 3 is left as an exercise for the reader. */
44 }
45
main()46 int main ()
47 {
48 test(0, 0, 0, 0);
49 test(-1, -1, -1, 1);
50 test(0x10000000, 0x10000000, 0x12345678, 2);
51 test(0x10000000, 0x20000000, 0x12345678, 2);
52
53 test(-1, 3, -3, 0);
54 test(0, -1, -1, 1);
55 test(-1, 0x10000000, 0x12345678, 2);
56 test(0x10000000, 0x7fffffff, 1, 3);
57
58 return 0;
59 }
60